Three charges (q1 = 6 C, q2 = -5.6 C, and q3 = 3.8C) are located at the vertices
ID: 2002239 • Letter: T
Question
Three charges (q1 = 6 C, q2 = -5.6 C, and q3 = 3.8C) are located at the vertices of an equilateral triangle with side d = 9.7 cm as shown.
1) What is F3,x, the value of the x-component of the net force on q3?
What is F3,y, the value of the y-component of the net force on q3?
2)A charge q4 = 3.8 C is now added as shown.
a- What is F2,x, the x-component of the new net force on q2?
b- What is F2,y, the y-component of the new net force on q2?
c- What is F1,x, the x-component of the new net force on q1?
Explanation / Answer
2)
"F2x" = -(9*10^9)*[{(q1*q2)/d^2} + {((q3 + q4)*q2)/d^2}*cos 60]
= -(9*10^9)*{q2/d^2}*[{(q1+ {(q3 + q4)/2}]
= -(9*10^3)*{(5.6)/(0.097)^2}*[6 + 0.5*(3.8+3.8)]
= -(9*10^3)*{(5.6)/(0.097)^2}*9.8 = -5.249*10^7 N
"F2y" = 0 as q3 = q4
"F1x" = (9*10^9)*[{(q1*q2)/d^2} - {((q3 + q4)*q1)/d^2}*cos 60]
= (9*10^9)*{q1/d^2}*[{(q2-{(q3 + q4)/2}]
= (9*10^3)*{(6)/(0.097)^2}*[5.6 - 0.5*(3.8+3.8)]
= (9*10^3)*{(6)/(0.097)^2}*1.8 = 10.3*10^6 N
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