12.) Two capacitors, C 1 = 4.00 µF and C 2 =15.0 µF, are connected in parallelan
ID: 1665908 • Letter: 1
Question
12.) Two capacitors, C1 = 4.00 µF and C2 =15.0 µF, are connected in paralleland the resulting combination is connected to a 9.00 V battery. (a) What is the equivalent capacitance of thecombination?____________ µF
(b) What is the potential difference across each capacitor?
C1 = ____________ V
C2 = ____________ V
(c) What is the charge stored on each capacitor?
C1 = _____________ µC
C2 = _____________ µC (a) What is the equivalent capacitance of thecombination?
____________ µF
(b) What is the potential difference across each capacitor?
C1 = ____________ V
C2 = ____________ V
(c) What is the charge stored on each capacitor?
C1 = _____________ µC
C2 = _____________ µC
Explanation / Answer
Given : C1 = 4.00 µF and C2 =15.0 µF V = 9.0 V Capacitors inparallel a ) Ceq = C1 + C2 = 4 + 15 = 19 F C = q / V q = Ceq V = ( 19 F ) ( 9 V ) = 171 C V1 = q / C1 = -------- v V2 = q / C2 = ----------v c ) As we know that charge stored in acapacitor C = q /V q1 = C1 V1 = ----- C q2 = C2 V2 = ----- C Plugin the values and solve itRelated Questions
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