Sucrose is allowed to diffuse along a 8.0 cm length of tubeingfilled with water.

Question

Sucrose is allowed to diffuse along a 8.0 cm length of tubeingfilled with water. The tube is 5.6 cm^2 in cross sectional area.The diffusion coefficient is equal to 5.0*10^-10 m^2/s, and8.0*10^-14 kg is transported along the tube in 19 s. What is thedifference in the concentration levels of sucrose at the two endsof the tube? answer in kg/m^3 Sucrose is allowed to diffuse along a 8.0 cm length of tubeingfilled with water. The tube is 5.6 cm^2 in cross sectional area.The diffusion coefficient is equal to 5.0*10^-10 m^2/s, and8.0*10^-14 kg is transported along the tube in 19 s. What is thedifference in the concentration levels of sucrose at the two endsof the tube? answer in kg/m^3

Explanation / Answer

Given :

Length ( L ) = 8.0 cm = 0.08 m

Area ( A ) = 5.6 cm2 = 5.6 * 10-4m

The diffusion coefficient ( D ) = 5.0*10-10 m2/s

Amount of mass transported ( m ) = 8.0*10-14kg

Time ( t ) = 19 s

   According to flick flow

     m / t = D A ( C2- C1 ) / L

   The difference in concentration levels of sucroseat the two ends of the tube is

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