A crow is flying horizontally with a constant speed of 2.60m/s whenit releases a

Question

A crow is flying horizontally with a constant speed of 2.60m/s whenit releases a clam from its beak. The clam lands on the beach2.90sec later. (let upward be the positive y direction)
a) Just before the clam lands, what is its horizontalcomponent of velocity? b) Just before the clam lands, what is its verticalcomponent of velocity? c) How would answer to part A change if the speed of thecrow were increased? d) How would your answer to part B change if the speedof the crow were increased?
a) Just before the clam lands, what is its horizontalcomponent of velocity? b) Just before the clam lands, what is its verticalcomponent of velocity? c) How would answer to part A change if the speed of thecrow were increased? d) How would your answer to part B change if the speedof the crow were increased?

Explanation / Answer

   a.   Since no air resistanceis given and gravity works perpendicualr to the horizontalcomponent of velocity, the horizontal component of velocity willremain the same as it was when clam was released.    vx   =   ux   =   2.60   m/s    b.   When clam is released,vertical component of velocity is zero(uy   =   0).    First equation of motion is       vy   =   uy   +   g* t       final velocity of clam asit lands on thebeach   vy   =   0+ ( - 9.8) * 2.90   ( since upwards direction is taken as +ve,   g   =   -9.8   m/s2)       vy   =   -28.42   m/s    - ve sign indicates that the direction ofvy is downwards.    c.    The horizontal component of velocitywill always be equal to initial horizontal component of velocity.Hence if the speed of crow is increased, it will alsoincrease.    d.   Since vertical component of speedis not affected by the horizontal component, answer in partB will not be changed.

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