A crow is flying horizontally with a constant speed of 2.70m/s when it releases

Question

A crow is flying horizontally with a constant speed of 2.70m/s when it releases a clam from its beak. The clam lands on the rocky beach 2.70s later. Let upward be the positive y direction.

A) Just before the clam lands, what is its horizontal component of velocity?

B) Just before the clam lands, what is its vertical component of velocity?

C) How would your answer to part A changes if the speed of the crow were increased?

D) How would your answer to part B changes if the speed of the crow were increased?

Explanation / Answer

A) 2.70 m/s
Explanation: When the clam is released then its velocity at that time is the same as the velocity of the crow. The crow is moving horizontally at 2.70 m/s. Therefore, at the time the crow releases the clam, the clam's velocity = 2.70 m/s horizontally.
There is no force in horizontal direction. Therefore horizontal component of velocity does not change.

B) Upward is positive. The clam falls downward. Therefore vertical component of velocity
= -g * t = -9.8 * 2.70 = -26.48 m/s

(Note: Do not forget the negative sign)

C) increase
Explanation: Answer of part A is equal to crow's speed. If criw's speed increases, then answer to part A also increases.

D)stay the same
See the solution to part B. we do not use crow's speed anywhere

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