A person makes ice tea by adding ice to 1.8kg of hot tea,intially at 80 degrees

Question

A person makes ice tea by adding ice to 1.8kg of hot tea,intially at 80 degrees C. How many kilograms of ice, intially at 0degress C, are required to bring the mixture to 10 degrees C? I understand that Q=mCT I just don't know how to applyit to the problem and find the answer. A person makes ice tea by adding ice to 1.8kg of hot tea,intially at 80 degrees C. How many kilograms of ice, intially at 0degress C, are required to bring the mixture to 10 degrees C? I understand that Q=mCT I just don't know how to applyit to the problem and find the answer.

Explanation / Answer

mass of tea m = 1.8 kg initial temp of tea t = 80 oC mass of ice M =? initial temp of ice t ' = 0 oC Mixture temp T = 10 oC Heat lost by tea = heat gain by ice      mC dt = ML + MC dt ' where C = specific heat fo tea = 4186 J / kg oC            L = latent heat of fusion = 334.88 * 10 ^ 3 J / kg           dt =80-10 =70           dt ' =10-0 =10 plug the values weget 527436 = M [ (334.88*10^3) + 41860]                                         M = 1.4 kg

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