Is that point left of the origin, at theorigin, or right of the origin? left of

Question

Is that point left of the origin, at theorigin, or right of the origin? left of the origin at the origin right of the origin Correct Part B Find the location of the point where theelectric field is zero. Enter your answers using twosignificant figures separated by a comma. Is that point left of the origin, at theorigin, or right of the origin? left of the origin at the origin right of the origin Correct Part B Find the location of the point where theelectric field is zero. Enter your answers using twosignificant figures separated by a comma. left of the origin at the origin right of the origin Correct Part B Find the location of the point where theelectric field is zero. Enter your answers using twosignificant figures separated by a comma. left of the origin at the origin right of the origin Correct left of the origin at the origin right of the origin Correct left of the origin at the origin right of the origin Correct left of the origin at the origin right of the origin Correct left of the origin at the origin right of the origin Correct left of the origin at the origin right of the origin Correct left of the origin at the origin right of the origin Correct left of the origin at the origin right of the origin Correct left of the origin at the origin right of the origin Correct Part B Find the location of the point where theelectric field is zero. Enter your answers using twosignificant figures separated by a comma. left of the origin at the origin right of the origin Correct

Explanation / Answer

Modified: ---------- Given q = -2.0 * 10 ^ -6C           q ' =-6.0 * 10 ^ -6 C separation between q and q ' is r = 0.4 m +0.4 m =0.8 m Let the net electric field be zero at a distance xfrom q If Net electric field is zero at x then electricfield due to q = electric field due to q '               K q / x ^ 2 = Kq' / ( r-x)^2                      q / x ^ 2 = q ' / ( r-x)^2            ( r-x)/ x = [ q ' / q ]                         = 1.732             r-x = 1.732 x          0.8 -x =1.732 x from this   x = 0.2928 m Therfore the required position is   = - 0.4 m +0.2928 m                                                   = -0.1071 m i.e., required co ordinates = ( -0.1071 m , 0 )

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