Is my APA conclusion right including an interpretation of r^2? Make a conclusion
ID: 3172947 • Letter: I
Question
Is my APA conclusion right including an interpretation of r^2?
Make a conclusion with APA format, including an interpretation of r2.
There was a significant positive relationship between high income and healthy weight in professional woman, r = -0.93, p < .05. The higher your income, the healthier your weight will be. About 81% of variance in healthy weight was explained by amount of income = .81.
Correlations
weight_rc
income_rc
weight_rc
Pearson Correlation
1
-.931**
Sig. (1-tailed)
.000
N
10
10
income_rc
Pearson Correlation
-.931**
1
Sig. (1-tailed)
.000
N
10
10
**. Correlation is significant at the 0.01 level (1-tailed).
Correlations
weight_rc
income_rc
weight_rc
Pearson Correlation
1
-.931**
Sig. (1-tailed)
.000
N
10
10
income_rc
Pearson Correlation
-.931**
1
Sig. (1-tailed)
.000
N
10
10
**. Correlation is significant at the 0.01 level (1-tailed).
Explanation / Answer
The above conclusion does not seem correct. Here is the correct one:
There was a strong negative relationship found between high income and healthy weight in professional woman, r = -0.93, p < .05. In a negative correlation, if the value of one factor increases, value of other factor decreases and vice versa. Hence, The lower the income of professional woman, the healthier her weight will be.
The coefficient of determination, r 2, is useful because it gives the proportion of the variance (fluctuation) of one variable that is predictable from the other variable.It represents the percent of the data that is the closest to the line of best fit. Here we can see that r = -0.931, then r 2 = 0.864, which means that 86.4% of the total variation in healthy weight can be explained by the linear relationship between high income and healthy weight in professional women, which is a significant one.
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