A vertical container with base area measuring 14.0 cm by 17.0 cm isbeing filled

Question

A vertical container with base area measuring 14.0 cm by 17.0 cm isbeing filled with identical pieces of candy, each witha volumeof 54.0 mm3 and a massof 0.0202 g. Assume that the volume of theempty spaces between the candies is negligible. If the height ofthe candes in the container increases at the rateof 0.270 cm/s, at what rate (kilograms perminute) does the mass of the candies in the containerincrease? pieces of candy, each witha volumeof 54.0 mm3 and a massof 0.0202 g. Assume that the volume of theempty spaces between the candies is negligible. If the height ofthe candes in the container increases at the rateof 0.270 cm/s, at what rate (kilograms perminute) does the mass of the candies in the containerincrease?

Explanation / Answer

Density of candy = mass /volume =0.0202 *10-3 kg /54*10-9 m3 = 3.74*102kg/m3 Rate of increase of mass = rate of increase of volume * density                                      = rate of increase of height *area*density                                       =0.270*10-2*14.0*10-2*17.0*10-2*374                                       =2.4 *10-2 kg/sec                                       =1.442 kg/min

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