Physics for scientists and engineers 7th by SerwayJewett Chapter 10 problem 27 S

Question

Physics for scientists and engineers 7th by SerwayJewett Chapter 10 problem 27 Sidewalls thickness = .635 cm Tread thickness = 2.5 cm width of tread = 20.0 cm Assume the rubber has uniform density equal to 1.10 x103 Kg/m3. Find its moment of inertia aboutan axis through its center. Physics for scientists and engineers 7th by SerwayJewett Chapter 10 problem 27 Sidewalls thickness = .635 cm Tread thickness = 2.5 cm width of tread = 20.0 cm Assume the rubber has uniform density equal to 1.10 x103 Kg/m3. Find its moment of inertia aboutan axis through its center.

Explanation / Answer

   for the side wall we get    m = [(0.305 m)2 - (0.165m)2] (6.35 x 10-3 m) (1.10 x 103kg / m3)       = .......... kg    Iside = (1 / 2) (11.0 kg) [(0.330m)2 - (0.305 m)2]            =......... kg . m2    for the entire tire we get that    Itoatl = 2 Iside +Itread            =......... kg . m2

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