Now let\'s look at the potential gradient associated with a charged capacitor. S

ID: 1662023 • Letter: N

Question

Now let's look at the potential gradient associated with a charged capacitor. Suppose we have a parallel-plate capacitor. The plates are separated by 6.0 mm and carry charges of equal magnitude and opposite sign (Figure 1). The potential difference between the plates is 24.0 V. Let the potential of the negatively charged plate be zero; then the potential of the positive plate is+24.0 V. Draw an enlarged sketch of (Figure 1); on it, show (1) the electric field lines between the plates and (2) the cross sections of the equipotential surfaces for which the potential is +24.0 V, +18.0 V, +12.0 V, +6.0 V,and 0. Figure 1of2 6.0 mm

Explanation / Answer

As the total potential difference across the capacitor is 24 volt across 6 mm. Thus, from 3 mm from the negative or 3 mm from the positive plate, the potential is 12 volt.

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Now let\'s look at the potential gradient associated with a charged capacitor. S

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