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c ra lng to ur rec ras you nave not yet redeemed an access code f this Classr purc nasea access te you will no longer be able to see your WebAssign assignments or grades Get access now nllne. I ne grace perlod WTI end VVednesday, January 24 2018 at 12:00 AM +-12 points SerCP11 15.P.004. A small sphere of mass m 6.20 g and charge q. 28.1 nC is attached to the end of a string and hangs vertically as in the figure. A second charge of equal mass and charge 58.0 nC is located below the first charge a distance d = 2.00 cm below the first charge as in the figure g1 12 a) Find the tension in the string (b) If the string can withstand a maximum tension of 0.180 N, what is the smallest value d can have before the string breaks? cm Need Help? ReadIt Type here to search Ci A ENG

Explanation / Answer

The string has to support the weight of m1 and the force of attraction between the two charges (F)

W = mg = 0.0061 kg x 9.81 N/kg

W = 0.0598 N

F = k.q1.q2 / d^2

F = (9 x 10^9)(28.1 x 10^-9C)(58 x 10^-9C) / (0.02m)^2

F = 0.0366 N

Tension = (0.0598 + 0.0366)N

T = 0.0964 N

b)

Max electric force = 0.18 - W = (0.18 - 0.0598) = 0.12 N

F(max) = k.q1.q2 /d^2

d^2 = k.q1.q2 / F(max)

d^2 = (9 x 10^9)(28.1 x 10^-9)(58 x 10^-9) / 0.120

d^2 = 1.22235 x 10^-4

d(min) = 1.105 cm

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