https//edugen. wileyplus.com/edugen/lti/main.uni Halliday, Fundamentals of Physi

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https//edugen. wileyplus.com/edugen/lti/main.uni Halliday, Fundamentals of Physics, 10e Help I Sys nread) PRINTER VERSONACK Chapter 02, Problem 026 A muon (an elementary particle) enters a region with a speed of 5.13 x 105 m/s and then is slowed at the rate of 2.13 x 1014 m/s. How far does the muon take to stop? Number the tolerance is +1.2% Units SHOW HINT LINK TO SAMPLE PROBLEM VIDEO MINI-LECTURE MATH HELP MATH HELP MATH HELP MATH HELP LTNK TO TEXT Question Attempts: 0 of 6 used SAVE FOR LATER SUBKIT

Explanation / Answer

Solution:

Let us go to the basics first.

From Newton's equation of motion, we know that:

v2 = u2 + 2as

[where, v= final speed = 0 as muon stops finally; s = distance; u = 5.13*106 m/s; a = -2.13*1014 m/s2 since slowing]

=>0 = u2 + 2as

=>s = -u2 / 2a

=>s = -(5.13*106)2 / [2*(-2.13*1014)] = 0.0617 m (Answer)

Thanks!!!

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