Forces in a Three-Charge System (EC) 4 of6 PartA Coulomb\'s law for the magnitud

Question

Forces in a Three-Charge System (EC) 4 of6 PartA Coulomb's law for the magnitude of the force F between two particles with charges Qand separated by a distance d is What is the net force exerted bythese two charges on a thed charge 480aCplaced between"and atz,--1120 m ? Your answer may be positive or negative, depending on the direction of the force Express your answer numerically in newtons to three significant figures. View Available Hints) where K-.and to-8.854 × 10-12O/(N.) is the permittivity of free space Consider two point charges located on the axis one charge, -.16 SnC is located at 1.660m:the second charge 39 5 nC, is at the origin(0.0000) Force on -2.93 10 Submt X Incorrect: Try Again; 5 attempts remaining

Explanation / Answer

Force on q3 due to q1 : F31 = k*q3*q1/r^2

= 9*10^9*(48*10^-9)*(16.5*10^-9)/(1.66 - 1.12)^2

= 2.44*10^-5 N directed towards left

Force on q3 due to q2 :

F32 = k*q3*q2/r'^2

= 9*10^9*(48*10^-9)*(39.5*10^-9)/(1.12)^2

= 1.36*10^-5 N directed towards left

So, net force on it = F32 + F31

= (2.44 + 1.36)*10^-5 = -3.8*10^-5 N (negative sign for direction towards left) <-------- answer

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