Forces in a Three-Charge System Coulomb\'s law for the magnitude of the force F

Question

Forces in a Three-Charge System Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is where K s and 4TE Eo 8.854 x 10 12 C2/(N m2) is the permittivity of free space Consider two point charges located on the X axis: one charge, q 16.0 nC is located at z1 -1.730 m the second charge, g2 35.0 nC, is at the origin (z 0.0000) Part A at is the net force exerted by these two charges on a third charge q3 51.0 nC placed between q1 and q2 at z3 1.185 m Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures. Force on q3 Submit Hints My Answers Give Up Review Part incorrect, Try Again; 4 attempts remaining Provide Feedback Continue

Explanation / Answer

here,

charge q1 = -16 nC

q1 = - 16 * 10^-9 C

charge q2 = 35 nC

q2 = 35 * 10^-9 C

x1 = - 1.73 m

x2 = 0

charge q3 = 51 nC

q3 = 51 * 10^-9 C

x3 = - 1.185 m

net force on q3 , F3 = k * q1 * q3/(x3- x1)^2 + k * q3 * q2/(x3- x2)^2

F3 = 9 * 10^9 * 16 * 10^-9 * 51 * 10^-9 /(0.545)^2 + 9 * 10^9 *35 * 10^-9 * 51 * 10^-9 /(1.185)^2

F3 = 3.62 * 10^-5 N

the net force on charge q3 is 3.62 * 10^-5 N towards the charge q1

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