Question 11 of 21 Map Sapling Learning macmillan learning For a single, isolated

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Question 11 of 21 Map Sapling Learning macmillan learning For a single, isolated point charge carrying a charge of q = 5.22 × 10-11 C, one equipotential surface consists of a sphere of radius 0.0224 m centered on the point charge as shown. What is the potential on this surface? Number 0.0224 m -- You would like to draw an additional equipotential surface which is separated by 9.66 V from the previously mentioned surface. How far from the point charge should this surface be? This surface must also meet the condition of being farther from the point charge than the original equipotential surface. Number

Explanation / Answer

1)The potential due to a charge q on a surface at a distnace r is given by kq/r where k is Coulomb constant

here:q=5.22*10-11 C, r=0.0224m, k=9*109

Potential on surface=kq/r=(9*109*5.22*10-11)/0.0224=20.97 V

2) Potential difference required between additional surface and original surface=9.66V

potential required at additional surface=20.97-9.66=11.31 V

Let the additional surface be at a distance r from the charge q

11.31=(9*109*5.22*10-11)/r

r=0.0415m

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