Help! 2. -4 points SerPSE9 7 P015 M A particle is subject to a force Fx that var

Question

Help! 2. -4 points SerPSE9 7 P015 M A particle is subject to a force Fx that varies with position as shown in the following figure. F (N) x (m 02 4 6 8 10 12 14 16 (a) Find the work done by the force on the partide as it moves from x 0 to x -4.00 m. oun (b) Find the work done by the force on the particle as it moves from x = 5.00 m to x = 9.00 m. (c) Find the work done by the force on the particle as it moves from x - 12.0 m tox 15.0 m. (d) What is the total work done by the force over the distance x - 0 to x- 15.0 m? Need Help? ReadWarch Watch It

Explanation / Answer

Work Done is area under the graph

(A.) Work = Area of triangle = 0.5 * b * h = 0.5 * 4 * 2.5 = 5J

(B.) Work = Area of rectangle= l * b = 4 * 3 = 12J

(C.) Work =Area of triangle = 0.5 * b * h = 0.5 * 1.5 * 3 = 2.25J

(D.) Work = Area of Trapezoid = 15 + 7.5 + 7.5 = 30 J

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