4) In this experiment we will once again assume the string is massless. But what

Question

4) In this experiment we will once again assume the string is massless. But what if the string had a significant mass and a uniform density? Call the distance from the pulley to mass m, “y” and write a formula for the total mass hanging from the pulley.

5) If the measured force on the cart is a constant 1.2N, and the cart mass is 900grams, what will the slope of the velocity/time graph be?

================================================================================================

Update

Pic will not upload.

pic is of cart on a table top surface with a string a extended out to a pully with the string extending over the top of the pully and down the side of the table. The string is hanging down from the table and will have a weigth attached. the cart has M mass and the weight at the end of the string is m

      M weight

-----------------------   _______________

    X            X                                                O)      <== Pully

                                                                        |

      Cart                             string                     | string hanging over

                                                                      [ ] m Weight

Explanation / Answer

4) IF string had mass, then you'd have to take its weight into consideration. Let's say length of the string is L and mass m,
Mass per unit length = m/L
Mass of rope hanging = m*y/L
Total mass hanging would be = (m+m*y / L)

5) If force is 1.2 N and cart has mass of 900 gms or 0.9 kg,
its acceleration a = F/m
a = 1.2/0.9
a = 1.33 m/s2

Slope of velocity time is graph is acceleration therefore slope is 1.33 m/s2

Related Questions

Navigate

• Browse (All)
• Browse 4
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.