PM0304/100 Calculator incorrect Oncorrect . Print Periodic Table of 13 pling Lea

Question

PM0304/100 Calculator incorrect Oncorrect . Print Periodic Table of 13 pling Learning Ma Three people pull sim force of 71.3 N, Jill pulls with 72.7 N in a direction 45 to the left, and Jane pulls in a direction 45° to the right with 105 N. (Since the donkey is involved with such uncoordinated people, who can blame it for being stubborn?) Find the magnitude of the net force the people exert on the donkey on a stubborn donkey. Jack pulls directly ahead of the donkey with a Number What is the direction of the net force? Express this as the angle from straight ahead between 0° and 90 with a positive sign for angles to the left and a negative sign for angles to the right. Number Tools 10 O Previous Check Answer Next Exit

Explanation / Answer

Force by Jack, F1 = 71.3 i
Force by Jill, F2 = 72.7/2 i + 72.7/2 j
Force by Jane = 105/2 i - 105/2 j
Net force, F
= F1 + F2 + F3
= 71.3 i + (72.7/2 i + 72.7/2 j) + (105/2 i - 105/2 j)
= 196.9 i - 23.19 j
=> magnitude of net force
= [(196.9)^2 + (23.9)^2]
= 198.26N

b)
angle from east to south
= -tan-1(23.9/196.9)=-6.9o

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