PLease hsow steps and please help me get the correct answer (2) . The team monit

Question

PLease hsow steps and please help me get the correct answer

(2). The team monitoring a space probe exploring the outer solar system finds that radio transmissions from the probe take 2.56 hours to reach earth. How distant (in meters) is the probe?

ANS_________________ m

(3). FM radio waves have frequencies between 85.5 MHz and 106.0 MHz. What is the shortest wavelength for these waves?

ANS___________________ m

(4). Two astronauts are 1.6 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via electromagnetic waves. The time it takes for sound waves to travel at 338 m/s through the air between the astronauts equals the time it takes for the electromagnetic waves to travel to the earth. How far away from the earth is the spaceship?

ANS______________________ m

PLease hsow steps and please help me get the correct answer (1). For each of the three sheets of polarizing material shown in the drawing, the orientation of the transmission axis is labeled relative to the vertical. The incident beam of light is unpolarized and has an intensity of 1340.0 W/m2. What is the intensity of the beam transmitted through the three sheets when (2). The team monitoring a space probe exploring the outer solar system finds that radio transmissions from the probe take 2.56 hours to reach earth. How distant (in meters) is the probe? ANS_________________ m (3). FM radio waves have frequencies between 85.5 MHz and 106.0 MHz. What is the shortest wavelength for these waves? ANS___________________ m (4). Two astronauts are 1.6 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via electromagnetic waves. The time it takes for sound waves to travel at 338 m/s through the air between the astronauts equals the time it takes for the electromagnetic waves to travel to the earth. How far away from the earth is the spaceship? ANS______________________ m theta 3 = 100.0½ ? ANS:_______________ W/m2 theta 2 = 57.0½ and theta 1= 19.0½,

Explanation / Answer

1)

I = (1340.0) (1/2) cos2(57-19) cos2(100-57)

==> I = 223 W/m2

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2)

x = c t = (3e8) * (2.56 * 60 * 60) = 2.76 x 10^12 m

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3)

wavelength = c/f = (3e8)/(106e6) = 2.83 m

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4)

tlight = tsound

xlight/vlight = xsound/vsound

(xlight)/(3e8) = (1.6)/(338)

==> xlight = 1.42 x 10^6 m

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