Item 4 Part A IP A parallel-plate capacitor has plates with an area of 1.0x10-2

Question

Item 4 Part A IP A parallel-plate capacitor has plates with an area of 1.0x10-2 m2 and a separation of 0.80 mm. The space between the plates is filled with a dielectric whose dielectric constant is 1.8 What is the potential difference between the plates when the charge on the capacitor plates is 4.1 C ? Express your answer using two significant figures. Submit My Answers Give Up Part B Will your answer to part A increase, decrease, or stay the same if the dielectric constant is increased? O Increase O Decrease Stay the same Submit My Answers Give Up Continue

Explanation / Answer

Given area A = 1 * 10^-2 m^2

seperation distance d = 0.8 m

dielectric constant k = 1.8

the capacitance is given by

C = k * epsilonot * A / d

C = (1.8 * 8.854 * 10^-12 * 10^-2) / 0.8

C = 1.99 * 10^-13 F

part A)

the potential difference is

V = Q / C

V = (4.1 * 10^-6) / (1.99 * 10^-13)

V = 2.06 * 10^7 V

part B)

the potantial difference is   V = V0 / k

as dielectric increases the potential difference decreases

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