. -n polrts SerCP10 4 PO45.MI.FB. Notes O Ask Your Teache Objects with masses m1

Question

. -n polrts SerCP10 4 PO45.MI.FB. Notes O Ask Your Teache Objects with masses m1 -11.0 kg and m2-7.0 kg are connected by a light string that passes over a frictionless pulley as in the figure below. If, when the system starts from rest, m2 falls 1.00 m in 1.32 s, determine the coefficient of kinetic friction between my and the table. which has greater value, a newton of goid on Earth or a newton of gold on the Moon? The newton of gold on the Moon. The newton of gold on the Earth The value is the same, regardless Need Help? Lerer ening Saed 20 4 3 W E

Explanation / Answer

let the acceleration is a

as it falls 1 m in 1.32 s

1 = 0.50 * a * 1.32^2

a = 1.15 m/s^2

let the coefficient of friction is u

for the acceleration

a * total mass = net force

a * (11 + 7) = 7 * 9.8 - u * 11 * 9.8

1.15 * (11 + 7) = 7 * 9.8 - u * 11 * 9.8

solving for u

u = 0.44

the coefficient of friction is 0.44

16) a newton gold on earth will have less mass

as F = m * g

and g is lower on Moon

hence , the mass of gold will be more

hence , The Newton of gold on moon will have more value

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