answer all the questions QUESTION 1 2 points Save Answer In this lab, we use two

Question

answer all the questions

QUESTION 1 2 points Save Answer In this lab, we use two different methods to determine image magnification, one by measuring object and image height, one by measuring object and image distance. The magnification determined by the first method is 6.96; by the second method 6.86. What is the percent difference? (Percent difference can be a positive or zero value. Please refer to the lab handout for formula ) QUES TION 2 2 points Save Answer In your experiment , an image is formed on a screen. You notice the object distance is greater than the image distance. Which of the following choices best describes the properties of the image? o Virtual Smaller o Virtual, Larger o Real, Smaller o Real, Larger QUESTION 3 2 points Save Answer In lab, an inverted image is observed. When the image height is used in calculation, what sign should it be? o Positive o Negative o Either can be used.

Explanation / Answer

Question no1 .Percentage difference,=(6.96-6.86)/(6.96)=1.436=1.4%

Question no 2. Magnification is given by , m= V/u,

It is given that u>V, also u and V are of opposite sign, thus mod ,m <1, and negative , therefore image is real and smaller

Question 3.sign of inverted image is positive

Quest.4.magnification is negative and greater than 1.Thus image is inveinverted and enlarged. Thus bot are correct.

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