answer a and b questions uliun Watch Y In a two-dimensional tug-of-war, Alex, Be
ID: 1390420 • Letter: A
Question
answer a and b questions
Explanation / Answer
a) Now the divide the force acting on the tug-of-war along the horizontal x - direction and vertical y-direction
Fx = 0
==> Fc cos@ - FA cos62 = 0
==> cos@ = FA cos62 / Fc
= 218 cos62 / 188
= 0.5443
==> @ = 57.01 deg
Now along the vertical direction
Fy = 0
==> FA sin62 + Fc sin57.01 - FB = 0
==> FB = 218 sin62 + 188 sin57.01
= 350.18 N
-----------------------------------------------------------------------------------------------
(b)
along the horizontal direction
FA cos62 + Fc cos (270-@ ) = 0
==> cos (270 -@ ) = - FA cos62 / Fc
- sin@ = - 218 * cos62 / 188
@ = 33.0 deg
along the vertical direction
FA sin62 - Fc sin33 - FB = 0
==> FB = 218 sin62 - 188 sin33
= 90.07 N
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.