the quarterback of a football team release a pass at height of 6 feet above the
ID: 1656915 • Letter: T
Question
the quarterback of a football team release a pass at height of 6 feet above the playing field, an the football is caught by receiver 35 yards directly downfield at a height of 3 feet. The pass is release at an angle of 35 degree with the horizontal. Find the speed of the football when it is released. Find the maximum height of the football. Find the time the receiver has to reach the proper position after the quarterback release the ball.the quarterback of a football team release a pass at height of 6 feet above the playing field, an the football is caught by receiver 35 yards directly downfield at a height of 3 feet. The pass is release at an angle of 35 degree with the horizontal. Find the speed of the football when it is released. Find the maximum height of the football. Find the time the receiver has to reach the proper position after the quarterback release the ball.
the quarterback of a football team release a pass at height of 6 feet above the playing field, an the football is caught by receiver 35 yards directly downfield at a height of 3 feet. The pass is release at an angle of 35 degree with the horizontal. Find the speed of the football when it is released. Find the maximum height of the football. Find the time the receiver has to reach the proper position after the quarterback release the ball.
Explanation / Answer
in vertical,
ay = -32.17 ft/s^2
v0y = v0 sin35
y = yf - yi = 3 - 6 = - 3 ft
y = v0y t + ay t^2 / 2
- 3 = v0 sin35 t - 32.17 t^2 /2 ..... (i)
in horizontal.
35 x 3 ft = v0 cos35 t
v0 t = 128.18
putting in(i)
-3 = 128.18 sin35 - 32.17 t^2 /2
t = 2.18 sec
speed = 128.18 / 2.18 = 58.8 ft/s .........Ans
0^2 - (v0 sin35)^2 = 2 (-32.174) (Hmax)
Hmax = 17.7 ft from initial position.
Hmax from ground = 17.7 + 6 = 23.7 ft .....Ans
t = 2.18 sec .......Ans
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