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How does your transformation efficiency compare with the different teams? Calcul

ID: 165637 • Letter: H

Question

How does your transformation efficiency compare with the different teams? Calculate the transformation efficiency of the following experiment using the information and results listed below: DNA plasmid concentration = 0.08ug/ul 250ul CaC12 transformation solution 10ul pGLO plasmid solution 250ul LB Broth 100ul cells spread on agar 227 colonies of transformants Show your calculations, and answer the following: What number of colonies were on the LB/amp/are plate? How much DNA was spread on the plate in ug? What is the transformation efficiency? If a particular experiment known to have 3 times 10 bacteria/ug DNA, how many transformant colonies would be expected to grow on the LB/amp/are plate? You can assume that the concentration of DNA and fraction of cells spread on the LB agar are the same as that of the pGLO laboratory.

Explanation / Answer

question 1 --Different tranformation protocol are used in laboratories for checking the efficiency and concentration of plasmid used in molecular biology.The range of number of colonies after transformation are from 800-7000. The different methods include calcium chloride method, inoue method of transformation.

question-2--DNA plasmid concentration=0.08microgram/microlitre, total plasmid DNA concentration=0.08 x 10=0.8 microgram of pGLO in 10 microlitre of solution.

volume of solution sread on agar plate=100 microlitre, so total volume=100+10 =110 microlitre.

250 microlitre of calcium chloride transformation solution in 250 microlitre of LB media and 10 microlitre of plasmid pGLO solution, so total volume=510microlitre.

so ratio of bacterial cells spread on plate/ total volume used for transformation with pGLO plasmid=100/510=0.196.

plasmid pGLO concentration x total volume of transformation=0.8 x 0.196=0.1568 microgram.

Answer--transformation efficiency=volume of bacterial cells plated/plasmid pGLO concentration in a defined volume used for transformation=100/0.1568=637.75=6.37x 102 colonies/microgram of pGLO plasmid.

1)answer--number of colonies on LB plate/amp/arabinose=6.37 x 102 colonies per microgram of pGLO plasmid used for transformation.

2)answer--plasmid DNA spread on the LB plate=0.1568 microgram.

3)answer--transfromation efficiency=6.37 x 102colonies per microgram of pGLO plasmid used for transfromation.

question-3--number of colonies of bacteria--3 x 10 bacteria/microgram of DNA=30 bacteria/microgram of plasmid DNA, volume of plasmid DNA used for transformation=10 microlitre, volume spread on LB agar plate=100 microlitre, concentration of plasmid DNA in 10 microlitre volume solution=0.8 microgram.

1 microgram of plasmid DNA present in 30 bacteria colonies, so 0.8 microgram in 10microlitre of plasmid DNA solution contain 30 x 0.8=24 bacteria colonies in 100 microlitre of solution spread on LB plate.

answer-24 transformation bacteria colonies in 100 microlitre of solution spread on plate.

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