The work done by an external force to move a -5.60 C charge from point a to poin
ID: 1654733 • Letter: T
Question
The work done by an external force to move a -5.60 C charge from point a to point b is 6.20×104 J .Part A - The work done by an external force to move a q charge from point a to point b is W. (a) If the charge was started from rest and had K of kinetic energy when it reached point b, what must be the potential difference between a and b? If the charge was started from rest and had 2.00×104 J of kinetic energy when it reached point b, what must be the potential difference between a and b?
Vb - Va = _________ V
Explanation / Answer
use work-energy theorem :-
work done = increase in kinetic energy + increase in potential energy
work done = increase in kinetic energy + q * V
6.20*10^-4 = 2.00*10^-4 + (5.60*10^-6) * V
(5.60*10^-6) * V = 4.20*10^-4
V = 75 Volts
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