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The woman marked with a question mark is your friend. Knowing that you are takin

ID: 186790 • Letter: T

Question

The woman marked with a question mark is your friend. Knowing that you are taking Genetics, she comes to ask you for advice: she wants to have children, but is afraid that they will be sick with the disease. Her husband and her mother have no family history of HD. What is the probability that she is sick? What is the probability that her children will be, without knowing her own status regarding the disease?

a. P(friend sick) = 1; P(child sick) = ½

b. P(friend sick) = 0; P(child sick) = 0

c. P(friend sick) = ¼ ; P(child sick) = 1/16

d. P(friend sick) = ½  ; P(child sick) = ¼  

OFemale with HD (Hh) O Normal Female (hh) Male with HD (Hh) Normal Male (hh)

Explanation / Answer

The correct answer is option D that is woman has Probablity of 1/2 getting affected and child having 1/4 probability of getting affected.

The woman's father is affected and mother is not affected.

So, Hh x hh will have 1/2 probability of getting Hh that is the genotype of getting affected.

So, if the mother is affected then the probability is 1/2.

Her husband is not affected that means he has the phenotype of hh. So, probability of getting Hh from the Hh x hh is 1/2 and the mother has chance of getting affected is 1/2. So, 1/2*1/2 will have probability of 1/4.

That is why Option D is the correct answer.