A child in danger of drowning in a river is being carried down-stream by a curre

Question

A child in danger of drowning in a river is being carried down-stream by a current that flows uniformly with a speed of 3.10 m/s . The child is 300 m from the shore and 2600 m upstream of the boat dock from which the rescue team sets out.

Part A

If their boat speed is 8.40 m/s with respect to the water, at what angle from the shore should the pilot leave the boat dock to go directly to the child?

Express your answer with the appropriate units.

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Explanation / Answer

let theta be the angle made by the boat

along the river

distance traveleld x = Vb*costheta*t

perpendicualr to the river

distance travelled y = vb*sintheta*t

tantheta = y/x

tantheta = 300/2600

theta = 6.58 degrees         <<<<<<===========ANSWER

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