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The charge on each plate is then Q = CV = (1.1 times 10^-10 F)(10.0 V) = 1.1 tim

ID: 1654628 • Letter: T

Question

The charge on each plate is then Q = CV = (1.1 times 10^-10 F)(10.0 V) = 1.1 times 10^-9 C Why did the author first calculate the capacitance and then calculate the charge? The energy stored in the capacitor is U = 1/2 CV^2 = 1/2 (1.1 times 10^-10 F)(1.0 v)^2 = 5.3 times 10^-9 Examine Example 23.1 in your text. State one similarity and one difference between the book example and the worked example. Does the shape of the plates matter? Again, referring to Example 23.1, the text's author states in the Interpret section, "Because the plates' area is much larger than their separation, we can treat the (electric) field between then as uniform." For any capacitor shape, where is the internal electric field not uniform? Examine Example 23.2 in your text. When comparing two capacitors' energy storage abilities, which aspect seems to be more important in increasing the energy storage capacity?

Explanation / Answer

2)

when a voltage is applied to these plates an electrical current flows charging up one plate with a positive charge with respect to the supply voltage and the other plate with an equal and opposite negative charge.

Then, a capacitor has the ability of being able to store an electrical charge Q (units in Coulombs) of electrons. When a capacitor is fully charged there is a potential difference, p.d. between its plates, and the larger the area of the plates and/or the smaller the distance between them (known as separation) the greater will be the charge that the capacitor can hold and the greater will be its Capacitance.

4)

Constant electric field is just the electric field due to the plate capacitor, but every proton and electron in the wire also produces its own electric field and the electrons in the wire respond to the total field, even the fields due to the other electrons and protons in the wire.

If a not-straight wire is curving away (maybe into other parts of the circuit) and away from the space between the capacitors, then the charges in the wire are not inside the electric field the whole time.

5)

Using capacitors as energy storage devices in circuits has potential applications for hybrid electric vehicles, backup power supplies, and alternative energy storage.
a "dry" or "solid" supercapacitor made of an amorphous TiO2 surface with nanometer-sized cavities provides better performance than typical supercapacitors that use liquid solvents. The researchers' earlier work on these dry TiO2 capacitors showed that they have several advantages for energy storage, such as a large capacitance of 4.8 F, wide operating temperature range from 193 to 453 K, and large voltage variation from 10 to 150 V.

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