A -2 80 mu C point charge is fixed at the origin of the .t axis A -7 80 mu C poi

Question

A -2 80 mu C point charge is fixed at the origin of the .t axis A -7 80 mu C point charge of mass I 50 grams is moving (in the -x direction) toward the charge at the origin. It has a speed of 22 0 m/s when it is at x = 0.800 m. Calculate (a) the total energy of the -7 80 mu C when it is at x = 0.800 m 0.609 J (b) the position along the .v axis where the speed of the -7 80 mu C charge is zero 0.323 m Two infinite parallel planes are separated 0.22 cm The planes have equal and opposite charge densities. The charge density of the positive plane is 9 4 mu C/m^2. Calculate (a) the magnitude of the electric field between the planes 1.1 MV/m (b) the potential difference from the positive plane to the negative plane -2.3 kV (c) the potential along the equipotential surface 0.10 cm from the positive plate. Let the potential along the positive plane equal 3.0 kV 1.9 kV

Explanation / Answer

1)

here,

Q1 = - 2.8 uC

Q2 = - 7.8 uC

m2 = 0.0015 kg

speed , v2 = 22 m/s

a)

the total energy of - 7.8 uC , TE = 0.5 * m2 * v2^2 + k * Q1 * Q2/0.8^2

TE = 0.5 * 0.0015 * 22^2 + 9 * 10^9 * 2.8 * 10^-6 * 7.8 * 10^-6 /0.8^2

TE = 0.609 J

b)

let the position along the x axis be x

as the total energy remains constant

TE = kinetic energy + electric energy

0.609 = 0 + 9 * 10^9 * 2.8 * 10^-6 * 7.8 * 10^-6 /x^2

solving for x

x = 0.323 m

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