A +13 nC charge is located at the origin. A)What is the electric field at the po

Question

A +13 nC charge is located at the origin.

A)What is the electric field at the position (x1,y1)=(5.0 cm, 0 cm)? Write electric field vector in component form.Enter the x and y components of the electric field separated by a comma. B)What is the electric field at the position (x2,y2)=(-5.0 cm, 5.0 cm)? Write electric field vector in component form.Enter the x and y components of the electric field separated by a comma.

C) What is the electric field at the position (x3,y3)=(-5.0 cm, -5.0 cm)? Write electric field vector in component form.Enter the x and y components of the electric field separated by a comma.

Explanation / Answer

(a)

q = 13 nC

r = 5 cm

Electric field E = k*q / r^2

E = 9*10^9*13*10^(-9) / (0.05)^2 = 46800 N

Ex , Ey = (46800 i , 0) N/C

(b)

r = sqrt (5^2 + 5^2) = 7.07 cm

E = 9*10^9*13*10^(-9) / (0.0707)^2 = 23407.068 N/C

Ex = -23407.06*cos45 = -16551.29 N/C

Ey = 23407.06*sin45 = 16551.29 N/C

Ex , Ey = (-16551.29 i , 16551.29j) N/C

(c)

r = 7.07 cm

E = 9*10^9*13*10^(-9) / (0.0707)^2 = 23407.068 N/C

Ex , Ey = (-16551.29 i , -16551.29 j) N/C

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