1. Above illustrates a “strobe” picture showing cannonballs being shot out of a
ID: 1654338 • Letter: 1
Question
1. Above illustrates a “strobe” picture showing cannonballs being shot out of a ship at different speeds. One question a student may ask is: does the cannonball that travels the farthest (shot at the highest speed— cannonball #4) take longer to hit the water than the one that does not travel as far (cannonball #1)? Answer this question in the space below and explain why:
The horizontal lines in the picture are spaced at equal time intervals, which show each cannonball falls towards the water at the same rate. It takes 2.1 seconds for each cannonball to hit the water. Using the Equations of Motions taught in class (show your work to get full credit):
a. Calculate how fast cannonball #1 would be going when it hits the water:
b. Calculate the vertical velocity of cannonball #4 when it hits the water:
c. Calculate the vertical distance from the point the cannonball exits the cannon to the surface of the water:
The answers I got were:
a, 20.58 ms^-1
b, 20.58 ms^-1
c, 21.609 m
If someone could verify these answers or answer question 1, that would be great
227 AM /14/2017 Projectile Motion Pre-Lab Name: Lab Section: Date: PreLab Activity (10 points)-Complete prior to vour lab session & hand in at the START of lab. +2 e3 1. Above illustrates a "strobe" picture showing cannonballs being shot out of a ship at different speeds. One question a student may ask is: does the cannonball that travels the farthest (shot at the highest speed- cannonball 44) take longer to hit the water than the one that does not travel as far (cannonball #1)? Answer this question in the space below and explain why The horizontal lines in the picture are spaced at equal time intervals, which show each cannonball falls towards the water at the same rate. It takes 2.1 seconds for each cannonball to hit the water. Using the Equations of Motions taught in class (show your work to get full credit):Explanation / Answer
1)
No. All the cannonballs take the same time to hit the water.
After the cannonball is thrown, if we resolve the motion into horizontal and vertical components, we observe that along the horizontal direction there is no force acting on the cannonballs. So the horizontal component of the force is zero. In the vertical direction, the force acting is the force due to gravity, which is a contant. So the vertical component of the force on them is also same. Eventually when horizontal and vertical components are taken together, we get the same force and as a result each cannonball take the same time to hit the water.
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