1. A: What is the magnitude of the net electric force on charge A in the figure

Question

1.

A: What is the magnitude of the net electric force on charge A in the figure (Figure 1)? Assume that q1 = 0.50 nC and q2 = 3.6 nC .

Express your answer to two significant figures and include the appropriate units.

FA = ?? N

NOTE: the 5.85*10^5 is not accurate

_______________________________

2. A +13 nC charge is located at the origin.

A: What is the electric field at the position (x1,y1)=(5.0 cm, 0 cm)? Write electric field vector in component form.

Enter the x and y components of the electric field separated by a comma.

E1x,E1y = ??,?? N/C

B: What is the electric field at the position (x2,y2)=(-5.0 cm, 5.0 cm)? Write electric field vector in component form.

Enter the x and y components of the electric field separated by a comma.

E2x,E2y = ??,?? N/C

C: What is the electric field at the position (x3,y3)=(-5.0 cm, -5.0 cm)? Write electric field vector in component form.

Enter the x and y components of the electric field separated by a comma.

E3x,E3y = ??,?? N/C

Explanation / Answer

(1)

According to the concept of the electric field and charges

Given that

Charge q1=0.5 nC

Charge q2=3.6 nC

Now we find the net electric force at point A

The net electric force=k(q1q2/r^2+q1q/b^2) =9*10^9{[0.5*3.6*10^-18/0.02^2]+(0.5*-1.6*10^-28/0.01^2)}

=9*10^9{4500*10^-18+18000*10^-28}

=4.05*10^-5-1.62*10^-14

=4.05*10^-5 N

...................................

(2) ans

According to the concept of the electric field and charges

Given that

Charge q=13 nC

Now we find the electric field at point (5cm,0)

Electric field E=9*10^9*13*10^-9/(0.05)^2=4.7*10^4 N/c

Now we find the electric field at point (-5cm,5cm)

direction (theta)=tan^-1(5/-5)=135 degree

Electric field E=[9*10^9*13*10^-9/(0.05^2+0.05^2)=2.34*10^4 N/c

The electric field Ex=Ecos(theta)=2.34*10^4*cos(135)=-1.7*10^4 N/c

The electric field Ey=E sin(45)=2.34*10^4*sin(135)=1.7*10^4 N/c

Now we find the electric field at point (-5cm,-5cm)

direction (theta)=tan^-1(-5/-5)=45 degree

Electric field E=[9*10^9*13*10^-9/(0.05^2+0.05^2)=2.34*10^4 N/c

The electric field Ex=Ecos(theta)=2.34*10^4*cos(45)=1.7*10^4 N/c

The electric field Ey=E sin(45)=2.34*10^4*sin(45)=1.7*10^4 N/c

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