Two identical conducting spheres, fixed in place, attract each other with an ele

Question

Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.4768 N when separated by 50 cm, center-to-center. The spheres are then connected by a thin conducting wire. When the wire is removed, the spheres repel each other with an electrostatic force of 0.3345 N. What were the initial charges on the spheres? Since one is negative and you cannot tell which is positive or negative, there are two solutions. Take the absolute value of the charges and

enter the smaller value here

Enter the larger value here..

Explanation / Answer

Here ,

let the charges are x and y

for the initial force

9 *10^9 * x * y/.50^2 = - 0.4768

after they are touched

charge on both = (x + y)/2

for the force between two charge

9 *10^9 * ((x + y)/2)^2/.50^2 = 0.3345

solving for x and y

x = 1.7 *10^-6 C

y = - 7.8 *10^-6 C

the smaller charge is 1.7 *10^-6 C

the larger charge is 7.8 *10^-6 C

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