Two cars at rest are at a distance of 1000 m apart. At the same instant, they bo

Question

Two cars at rest are at a distance of 1000 m apart. At the same instant, they both accelerate toward each other. Car A accelerates at a rate of 1.50 m/s^2 while Car B accelerates at a rate of 2.50 m/s^2. a. How far will each car go before meeting each other? b. Find the time. Set up in IP and find the values and percent errors. For this problem, turn off gravity, and simulate the acceleration as before, setting the masses to 1.00 kg and applying the appropriate force vector. A ball is thrown directly upwards from a 40.0 m tall building with a speed of 36.0 m/s. It reaches max height then falls down, missing the edge of the building and continues to fall, hitting the ground. a. Find the maximum height reached by the ball and the time to reach max height b. Find the velocity of the ball when it returns to 40.0 m, and the time when this occurred c. Find the total time in the air and the impact velocity of the ball d. Find the position of the ball relative to the ground at t = 2.50 s after the toss e. What is the velocity of the ball and its direction of the motion at t = 2.50 s

Explanation / Answer

Given that

initial velocity u=0 m/s

car A accelerates =>Aa=1.5 m/s^2

carB accelerates =>Ab=2.5 m/s^2

now we find the time they are meet

S=S1+S2

1000=(ut+1/2Aat^2)+(ut+1/2Abt^2)

1000=(0+1/2*1.5*t^2)+(0+1/2*2.5t^2)

1000=0.75t^2+1.25t^2

1000=2t^2

t^2=500

time t=22.4 sec

now we find the distance of each car

distance of car A=>s1=1/2*1.5*22.4^2=376.3 m

distance of car B=>s2=1/2*2.5*22.4^2=627.2

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