From the top of a cliff, a person throws a stone straight downward. The initial

Question

From the top of a cliff, a person throws a stone straight downward. The initial speed of the stone just after leaving the person's hand is 9.6 m/s.
(a) What is the acceleration (magnitude and direction) of the stone while it moves downward, after leaving the person's hand?
(b) After 0.47 s, how far beneath the top of the cliff is the stone? (Give just the distance fallen, that is, a magnitude.)
From the top of a cliff, a person throws a stone straight downward. The initial speed of the stone just after leaving the person's hand is 9.6 m/s.
(a) What is the acceleration (magnitude and direction) of the stone while it moves downward, after leaving the person's hand?
(b) After 0.47 s, how far beneath the top of the cliff is the stone? (Give just the distance fallen, that is, a magnitude.)
From the top of a cliff, a person throws a stone straight downward. The initial speed of the stone just after leaving the person's hand is 9.6 m/s.
(a) What is the acceleration (magnitude and direction) of the stone while it moves downward, after leaving the person's hand?
(b) After 0.47 s, how far beneath the top of the cliff is the stone? (Give just the distance fallen, that is, a magnitude.)

Explanation / Answer

(a) stone will fall under gravity so acceleration will be 9.8 m/s² in downward direction.

(b) h = ut + ½at²

-h = (-9.6)×0.47 + (0.5)×(-9.8)×(0.47²)

h = 153.361 m

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