A marathon runner completes a 42.01 km course in 2h, 6min, and 43s. There is an

Question

A marathon runner completes a 42.01 km course in 2h, 6min, and 43s. There is an uncertainty of 25 m in the distance traveled and an uncertainty of 2 s in the elapsed time. In this problem you can approximate the percent error on a product or quotient of quantities by the sum of the percent error on each quantity.
Thank you in advance for your help!
A. Calculate the percent uncertainty in the distance. B. Calculate the percent uncertainty in the elapsed time. C. What is the average speed in meters per second? D. What is the uncertainty in the average speed in m/s?
A marathon runner completes a 42.01 km course in 2h, 6min, and 43s. There is an uncertainty of 25 m in the distance traveled and an uncertainty of 2 s in the elapsed time. In this problem you can approximate the percent error on a product or quotient of quantities by the sum of the percent error on each quantity.
Thank you in advance for your help!
A. Calculate the percent uncertainty in the distance. B. Calculate the percent uncertainty in the elapsed time. C. What is the average speed in meters per second? D. What is the uncertainty in the average speed in m/s?

Thank you in advance for your help!
A. Calculate the percent uncertainty in the distance. B. Calculate the percent uncertainty in the elapsed time. C. What is the average speed in meters per second? D. What is the uncertainty in the average speed in m/s?

Explanation / Answer

(A) percent uncertainty in the distance = (25 / 42010) x 100
  
= 0.06 %

(B) in the time = [ 2 / ((2 x 3600) + (6 x 60) + (43))] x 100

= 200 / 7603

= 0.03 %

(C) average speed = (42010 m ) / 7603 s

= 5.525 m/s

(D) % uncertainty = 0.06 + 0.03 = 0.09 %

uncertainty = (5.255 x 0.09) / 100 = 0.005 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.