Vectors Begin Date: 823/2016 12.00 00 AM -Due Date: 9762017 8:00.00 AM End Date:

Question

Vectors Begin Date: 823/2016 12.00 00 AM -Due Date: 9762017 8:00.00 AM End Date: 12/15/2017 800:00 AM (9%) Problem 10: A new landowner has a triangular piece of flat land she wishes to fence. Starting at the west comer, she measures the first side to be 84 m long andy the next to be 102 m. These sides are represented as displacement vectors A and B in the figure A+B+C- A. Ctheexpertta.com > She then correctly calculates the length of the third side c what is her result (in meters)? Grade Sammary Potential 100% 7 8 9 4 5 6 1 2 3 s tan Submissions Attermpts remaining S (1% per ameept) detailed vien cotan si acoso atanacotan0sinho cosh tanh0 cotanh0 Degrees ORadians Hint I give up Submit Feedback:-deduction per feedback. Hists: deduction per hint Hints remaining

Explanation / Answer

Given distances:

A = 84 m ; B = 104 m

Ay = 84 sin21 = 30.1 m ; Ax = 84 cos21 = 78.42 m

By = 104 sin11 =-19.84 m Bx = 104 cos11 = 102.08 m

X = 102.08 - 30.1 = 71.98 m

Y = 78.42 - 19.84 = 58.58 m

C = sqrt (71.98^2 + 58.58^2) = 92.80 m

theta = tan^-1(58.58/71.98) = 39.14 deg

Hence, C = 92.8 m ; theta = 39.14 deg

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