Vector A points 38° counterclockwise from the x axis.Vector B is twice as long a

Question

Vector A points 38° counterclockwise from the x axis.Vector B is twice as long as A. Their product A×B has lengthA2 and points in the negative zdirection. What is the direction of vector B? (Measure from thepositive x axis with the counterclockwise directionpositive.) B > 0 1° B < 0 2°
Vector A points 38° counterclockwise from the x axis.Vector B is twice as long as A. Their product A×B has lengthA2 and points in the negative zdirection. What is the direction of vector B? (Measure from thepositive x axis with the counterclockwise directionpositive.) B > 0 1° B < 0 2°
B > 0 1° B < 0 2°

Explanation / Answer

from the problemfind the angle between the vectors        A x B = A Bsin         A2 = A * 2A sin         1/2 = sin           = 30 0  or    150 0 the angle between A and B, so it looks like this:                 A is   380 from the x axis, so B couldbe      38 - 30 =  80 from the x axis                                                                 or B could be   38 - 150  = -1120 from the x axis

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