A grizzly bear is sitting on a rock in the middle of a calm river when she obser

Question

A grizzly bear is sitting on a rock in the middle of a calm river when she observes a fish directly below. If the apparent depth of the fish is 0.40 m, what is the actual depth at which the fish is swimming? The index of refraction of water is 1.33. A) 0.43 m B) 0.53 m C) 0.62 m D) 0.71 m E) 0.80 m Which one of the following statements is not a characteristic of a plane mirror? A) The image is real. B) The magnification is +1 C) The image is always upright. D) The image is reversed right to left. E) The image and object distances are equal in magnitude. An object is 1.0 m in front of a mirror. A virtual image is formed 10.0 m behind the mirror. What is the radius of curvature of the mirror? A) 4.4 m B) 2.2 m C) 1.1 m D) 0.56 m E) This problem cannot be solved without more information.

Explanation / Answer

10. B

Given

fish is in the water at an apparent depth d_a = 0.40m

refractive index of water is n = 1.33

real depth of the fish is D_r = ?

we know that the definition of refractive index is n = real depth / apparent depth

n = D_r/d_a ==> D_r = n*d_a = 1.33*0.4 m = 0.532 m = 0.53 m

answer is option B

11.A

among the given statements regarding plane mirror all the correct or the characteristics of plane mirror except the first option

The image is real

we know that th$e image formed by plane mirror is always a virtual image not a real image.

so the answer is option A

12. B

the object distance s = 1.0 m

image distance is s' = -10 m

radius of curvature is R = ?

we know the relation 1/s+1/s' = 2/R ==> 2/R = 1/1-1/10 = 2.22 m

the answer is option B

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