If 3.30 times 10^5 J of energy is supplied to a flask of liquid oxygen at -183 d

Question

If 3.30 times 10^5 J of energy is supplied to a flask of liquid oxygen at -183 degree C, how much oxygen can evaporate? kg A 24 g ice cube at its melting point is dropped into an insulted container of liquid nitrogen. How much nitrogen evaporates if it its boiling point of 77 K and has a latent heat of vaporization of 200 kJ/kg? kg A cube of ice is taken from the freezer at -9.1 degree C and placed in a 101 g aluminum calorimeter filled with 278 g of water at room temperature of 20 degree C. The situation is observed to be all water at 16 degree C. What was the mass of the ice cube? g

Explanation / Answer

1) Given,

Heat, Q = 3.30 x 105 J

Latent heat, Q = m L

3.30 x 105 = m x L

(Since, L= heat of vaporization for oxygen= 210 kJ/kg)

3.30 x 105 = m (210 x 103 J/kg)

Mass, m = 1.57 kg

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