Two insulated wires perpendicular to each other in the same plane carry currents
ID: 1647449 • Letter: T
Question
Two insulated wires perpendicular to each other in the same plane carry currents as shown in (Figure 1) . Assume that I = 10 A and d = 20 cm .
a)
Find the magnitude of the net magnetic field these wires produce at point P if the 10 A current is to the right (Current (a) in the figure).
b)Find the magnitude of the net magnetic field these wires produce at point Q if the 10 A current is to the right (Current (a) in the figure).
c)Find the magnitude of the net magnetic field these wires produce at point P if the 10 A current is to the left (Current (b) in the figure).
Explanation / Answer
(A) field due to wire of current I,
B1 = u0 I / (2 pi d) into the page
= (4pi x 10^-7 x 10) / (2 x pi x 0.20)
= 1 x 10^-5 T into he page
field due to wire of current 10 A to right
B2 = (4pi x 10^-7)(10) / (2 x pi x 0.08)
B2 = 2.5 x 10^-5 T into the page
B = B1 + B2 = 3.5 x 10^-5 T into the page
(B) field due to wire of current I,
B1 = u0 I / (2 pi d) into the page
= (4pi x 10^-7 x 10) / (2 x pi x 0.20)
= 1 x 10^-5 T out of page
field due to wire of current 10 A to right
B2 = (4pi x 10^-7)(10) / (2 x pi x 0.08)
B2 = 2.5 x 10^-5 T out of page
B = B1 + B2 = 3.5 x 10^-5 T out of page
(C)
field due to wire of current I,
B1 = u0 I / (2 pi d) into the page
= (4pi x 10^-7 x 10) / (2 x pi x 0.20)
= 1 x 10^-5 T into he page
field due to wire of current 10 A to right
B2 = (4pi x 10^-7)(10) / (2 x pi x 0.08)
B2 = 2.5 x 10^-5 T out of the page
B = B2 - B1 = 1.5 x 10^-5 T out of the page
(D) field due to wire of current I,
B1 = u0 I / (2 pi d) into the page
= (4pi x 10^-7 x 10) / (2 x pi x 0.20)
= 1 x 10^-5 T out of the page
field due to wire of current 10 A to right
B2 = (4pi x 10^-7)(10) / (2 x pi x 0.08)
B2 = 2.5 x 10^-5 T into the page
B = B2 - B1 = 1.5 x 10^-5 T into the page
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.