Two insulated wires perpendicular to each other in the same plane carry currents

Question

Two insulated wires perpendicular to each other in the same plane carry currents as shown in (Figure 1) . Assume that I = 14 A and d = 19 cm .

Part A

Find the magnitude of the net magnetic field these wires produce at point P if the 10 A current is to the right (Current (a) in the figure).

Part B

Find the magnitude of the net magnetic field these wires produce at point Q if the 10 A current is to the right (Current (a) in the figure).

Part C

Find the magnitude of the net magnetic field these wires produce at point P if the 10 A current is to the left (Current (b) in the figure).

Part D

Find the magnitude of the net magnetic field these wires produce at point Q if the 10 A current is to the left (Current (b) in the figure).

Explanation / Answer

part(A)

B1 = -uo*I1/(2*pi*d) into the page

B2 = -uo*I2/(2*pi*r2) into the page

Bnet = B1 + B2

Bnet = -(4*pi*10^-7/(2*pi))*(14/0.19 + 10/0.08) = -3.97*10^-5 T

magnitude = 3.97*10^-5 T <<<====answer

--------------------

part(B)

B1 = uo*I1/(2*pi*d) out of the page

B2 = uo*I2/(2*pi*r2) out the page

Bnet = B1 + B2

Bnet = (4*pi*10^-7/(2*pi))*(14/0.19 + 10/0.08) = 3.97*10^-5 T out of page

Bnet = 3.97*10^-5 T <<====answer

----------------------

part(C)

B1 = -uo*I1/(2*pi*d) into the page

B2 = +uo*I2/(2*pi*r2) out the page

Bnet = B1 + B2

Bnet = (4*pi*10^-7/(2*pi))*(-14/0.19 + 10/0.08) = 1.02*10^-5 T out of page

magnitude = 1.02*10^-5 T out of page   <<====answer

---------------

part(D)

B1 = uo*I1/(2*pi*d) out the page

B2 = -uo*I2/(2*pi*r2) in to the page

Bnet = B1 + B2

Bnet = (4*pi*10^-7/(2*pi))*(14/0.19 - 10/0.08) = -1.02*10^-5 T

magnitude = 1.02*10^-5 T out of the page    <<====answer

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