Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

c Secure https://www.flp unitltemID-2828397Benro ImentD 24850 Disk celeratisn of

ID: 1643831 • Letter: C

Question

c Secure https://www.flp unitltemID-2828397Benro ImentD 24850 Disk celeratisn of a Tennis Racket celeration of a Tennis Racket String and Pulley 4 5 Angular Velocity Graph Time (sec) Accoloration in Ecuador Spinning Disk t Disk Ihe graph above shows tho angular velocity at a nctating whoal a a tunction or time 1 What is the angular displacement of the wheel at t 23ec? Mountalin Bike rad Submit ) hat i the anglarispament ar the whoal at r- 31 ? rad Submit CA macmillan Copyright 2017 Freeman worth Publishers- division or Macmillan Lerm Nout I Tech Sxport Find Your Local Sales Rep Terus of use Priwaty Policy learning

Explanation / Answer

equation of the given line will be

(y - y1) = m*(x - x1)

m = (y2 - y1)/(x2 - x1)

m = (0 - (-9))/(3 - 0) = 3

y - 0 = 3*(x - 3)

y = 3x - 9

Now, y = angular velocity and t = time

w = 3t - 9

at t = 2.3 sec

w = 3*2.3 - 9 = -2.1 rad/sec

when t = 3.1 sec

w = 3*3.1 - 9 = 0.3 rad/sec

Now angular displacement will be given by the area between the curve,

A.

Area = Area of square part + area of triangle part

Area = 2.3*(-2.1) + 0.5*2.3*(-6.9)

Area = -12.765 rad

Angular displacement = -12.765 rad

B.

Area = area of lower triangle + area of upper triangle till t = 3.1 sec

A = 0.5*3*(-9) + 0.5*0.1*0.3

Area = -13.485 rad

Angular displacement = -13.485 rad

Let me know if you have any doubt.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at drjack9650@gmail.com
Chat Now And Get Quote