One strategy when on a diet is to drink ice water. The body must burn calories t
ID: 1643184 • Letter: O
Question
One strategy when on a diet is to drink ice water. The body must burn calories to warm the water from 0°C to a body temperature of 37°C. Assume a dieter drinks 2.3 kg (i.e., 2.3 L) of ice water every day. The specific heat of water is 4.186 × 103 J/(kg°C).
How much energy, in joules, does the dieter’s body need to provide in order to warm the water over a full year. Take 365 days in a year.
One pound of fat supplies 3400 kcal (Cal) to the body, where 1 kcal (Cal) = 4.186 × 103 J. How much fat, in pounds, can the dieter hope to lose in a year by drinking ice water rather than water at body temperature?
Explanation / Answer
Energy required in an year = m*c*deltaT
=2.3*365*4186*(37-0)
= 1.3*10^8 J answer
Pounds burnt = 1.3e8/(3400*4186)
= 9.134 pounds answer
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