One species of fern has a long chromosome of 1 times 10^7 base pairs. Each repli
ID: 223087 • Letter: O
Question
One species of fern has a long chromosome of 1 times 10^7 base pairs. Each replication fork moves at the rate of 1.000 base pairs per minute. If this chromosome contains a single origin of replication precisely in the middle, how long Would it take to replicate the entire chromosome? Show your math in fact. S phase in this gem is completed in 50 minutes. How man's origins of replication must there be (minimally) on this large chromosome in order for it lol replicate completely in 50 minutes? Show your math. What is the average number of base pairs per replicon (between adjacent origins of replication) on this large chromosome? Show your mathExplanation / Answer
(a) chromosome length = 1x10^7 base pairs
replication rate = 1000bp/s
Replication time = 1x10^7/1000*2 = 5000 mins for replicating the entire chromosome
(b) Since the S phase in this fern is completed in 50 mins, the number of replication origin should be 100.
(c) Avergae number of bps per replicon = chromosome length/number of replication origin
= 1x10^7/100 = 100000
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