du 3G 5:05 AM 41% HW2 summer 2017 Halliday, Fundamentals of Physics, 10e Chapter

Question

du 3G 5:05 AM 41% HW2 summer 2017 Halliday, Fundamentals of Physics, 10e Chapter 24, Problem 019 In the figure particles with charges q1 = +7e and q2 =-18e are fixed in place with a separation of d = 26.4 cm. With V = 0 at infinity, what are the finite (a) positive and (b) negative values of x at which the net electric potential on the x axis is zero? (a) Number (b) Number Click if you would like to show work for this q_ion: emsoew Question Attempts: O of 1 used SAVE POR LATER Copyright 2017 by ohn Wiley

Explanation / Answer

Net Electric potential is, V = kq1/r1 + kq2/r2

Factor out k since it appears in both terms
0 = 7e/x - 18e/(0.264 - x) where x is the net electric potential zero point on the x axis between the two charges that are 0.264 m apart.
7e/x = 18e/(0.264 - x) => 7e*(0.264 - x) = 18e*x => 1.848e - 7ex = 18ex => 1.848e = 25ex => x = 0.0739 m

Now look for V = 0 on negative x axis. Let x be the distance to the left of the origin
0 = 7e/x -18e/(0.264+x) => 7e*(0.264+x) = 18e*x => 1.848e + 7ex = 18ex => 1.848e = 11ex => x = 0.168 m left from the origin.

V = 0 at a) 0.0739 m and

b) - 0.168 m

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