How do you find the Graphical portion of this table? Forces on Ring (N) Resultan

Question

How do you find the Graphical portion of this table?

Forces on Ring (N) Resultant Force R (magnitude and direction) Masses to Use Experimental Analytical Graphical Section Am, 0.105 kg@ 30 Addition 1 | m2 : 0.105 kg @ 120° | T,3 Vector Section B: | nh : 0.105 kg @ 20 T-103 - Vector R= 1.51 N Addition 2 " 0075 kg @ 803 m=0.la__ kg | 127-NI = R: Section C 0.105 kg @ o 0.105 kg @ 0 Vector Addition 3 | m2 : 0.075 kg @ 90. | T, 3 m, 0.075 kg@ 90 = 3519-3555 Section D:0.105 kg@30 Vector | m2 : 0.105 kg @ 90° | T2=103| R: 2. IO Addition 4 m, 0055 kg @ 120" N = n,- .055 kg Section E: Vector | m: 0.105 kg @ 240° | E=10 Resolution

Explanation / Answer

The graphical value here means that you need to draw the space-diagram and then the corresponding vector-diagram of the given situation. As you have not attached the figure, I can be of little help but I am trying to explain it to you how it is to be done.

First draw the figure that is given neatly, with all the angles to the sclae ie. you draw the actual angles on the paper. After completing this, you now draw the vector diagram. CAlculate the known forces and select a suitable scale for eg if force is 100N, draw the scale 1cm=10N. Complete the force diagram like this. Remember, the directions of the forces are to be taken from the space diagram. Once you have completed, close the vector polygon to find the resultant.

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