A small particle has charge -4.20 C and mass 2.80×104 kg . It moves from point A

Question

A small particle has charge -4.20 C and mass 2.80×104 kg . It moves from point A, where the electric potential is VA = 290 V , to point B, where the electric potential VB = 570 V is greater than the potential at point A. The electric force is the only force acting on the particle. The particle has a speed of 3.40 m/s at point A.

Part A

What is its speed at point B?

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Part B

Is it moving faster or slower at B than at A?

Is it moving faster or slower at  than at ?

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Explanation / Answer

A) Kinetic energy = q*dV

0.5mv^2 = qdV

0.5*2.8*10^-4*v^2 = 4.2*10^-6*(570-290)

v = 2.9 m/s

B) The object will move slower at B

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